
Shostakovich Peninsula
(Alexander Island)
British Antarctic Territory
Location: 72° 10' 59" S 71° 19' 59" W
extending into Bach Ice Shelf between Williams Inlet and Stravinsky Inlet, S Alexander Island, was photographed from the air by the Ronne Antarctic Research Expedition in 1947 and roughly mapped from air photographs by the Falkland Islands Dependencies Survey in 1959; delineated from USLANDSAT imagery of January 1973; in association with the names of composers grouped in this area, named after Dmitri Shostakovich (1906-75), Russian composer.